Question

If X/b+c = Y/c+a = Z/a+b show that (b-c)X + (c-a)Y + (a-b)Z = 0

Answer 1

let x/b+c= y/c+a = z/a+b =k

therefore x = (b+c)k, y= (c+a)k & z = (a+b)k

acc. to the qs by putting all the value of x, y, z we get the result = 0