If x be the mean proportional of x-2 and x+6 then find x
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Answered by
25
x² = (x-2)(x+6)
∴ x² = x² + 6x - 2x - 12
∴ x² = x² + 4x - 12
∴ x² - x² = 4x -12
∴0 = 4x -12
∴4x = -12
∴ x = -12÷4
∴x = -3
∴ x² = x² + 6x - 2x - 12
∴ x² = x² + 4x - 12
∴ x² - x² = 4x -12
∴0 = 4x -12
∴4x = -12
∴ x = -12÷4
∴x = -3
ujjalneog:
thank u very much sir
Answered by
16
The value of x is 3.
* When a number, x is said to be the mean proportional of two other numbers( a and b), it means that the number, x lies in between a and b.
So, we can write as:
(x-2)/x = x/(x+6)
Or, x² = (x-2)(x+6)
Or, x² = x² + 6x - 2x - 12
Or, x² = x² + 4x - 12
Or, 4x -12 = 0
Or, 4x = 12
Therefore, x = 3
So, we can say that 3 is the mean proportional of two numbers 1 and 9.
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