Question

If x cube minus 6 x square + 6 x + k is completely divisible by x minus 3 then find the value of k

Answer 1

Answer: k = 9

Step-by-step explanation:

If p(x) = x^3 - 6x^2 + 6x + k is completely divisible by x - 3, then p(3) will be 0.

p(3) = (3)^3 - 6(3)^2 + 6(3) + k = 0

p(3) = 27 - 6 × 9 + 6 × 3 + k = 0

p(3) = 27 - 54 + 18 + k = 0

p(3) = - 9 + k = 0

k - 9 = 0

k = 9

So the value of k is 9.

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Answer 2

Answer:

Step-by-step explanation: