If x = cube root (2 + square root 3), then what is x cube + 1/x cube?
Answers
Answered by
47
put the value of x and then remove cube root then rationlise 1/2+√3 and put the value and solve u will get your answer as I had solve on that pic
Attachments:
Answered by
48
x³ + 1/x³ = 4 if x = ∛(2 + √3)
Step-by-step explanation:
x = ∛(2 + √3)
x³ + 1/x³
x = ∛(2 + √3)
cubing both sides
=> x³ = 2 + √3
1/x³ = 1/(2 + √3)
Rationalizing
=> 1/x³ = {1/(2 + √3) } * {(2 - √3)/(2 + √3)}
=> 1/x³ = (2 - √3) /(4 - 3)
=> 1/x³ = 2 - √3
x³ + 1/x³ = 2 + √3 + 2 - √3
=> x³ + 1/x³ = 4
Learn more:
X-1/x=3 find x^3-1/x^3
https://brainly.in/question/7310418
X^3+1/x^3=756 then x^4+1/x^4
https://brainly.in/question/12919188
if x3 + 3/x = 4 (a3 + b3) and 3x +3/x3 = 4 (a3 – b3) then,show that a2
https://brainly.in/question/13909845
Similar questions