Question

if x cube + x square + bx + 6 is divisible by x minus 2 and leaves remainder 3 when divided by x minus 3 find a and b

Answer 1

Answer:

Step-by-step explanation:

x3+x2+bx+6=p(x)

g(x)=x-2

P(2)=0

P(2)=2^3+2^2+b(2)+6=0

9+4+2b+6=0

19+2b=0

b= -19/2

Now according to question

g(x)=x-3

X=3

P(3)=a

P(3)=3^3+3^2+(-19/2)×3+6=a

27+9-57/2+6=a

42-57/2=a

27/2=a

Therefore a=27/2 & b= -19/2