If X=cy+bz, y=az+cx, z=bx+ayThen prove x^2/(1-a^2)=y^2/1-b^2=z^2/1-c^2
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x = cy + bz
y = az + cx
y = az + c^2y + cb
(1 - c^2)y = (a+bc)z
meanwhile
z = bx + ay
z = bcy + b^2z + ay
(1 - b^2)z = (a + bc)y
from first set:
y/(a+bc) = z/(1 - c^2)
(a + bc)y/(1 - b^2) = z
multiply left equation to left.. and right equation to right equation also .
y^2/(1 - b^2) = z^2/(1 - c^2)
then you can continue with the rest of the equation ... half of the part has already been done for you .
Don't forget to SUBSCRIBE my YouTube channel (BanarasiiiINDIA) if this answer is helpful for you.This is my YouTube channel Link-https://www.youtube.com/channel/UC27NLinpXVunbzVQ0vdHabQ
Thank You!
x = cy + bz
y = az + cx
y = az + c^2y + cb
(1 - c^2)y = (a+bc)z
meanwhile
z = bx + ay
z = bcy + b^2z + ay
(1 - b^2)z = (a + bc)y
from first set:
y/(a+bc) = z/(1 - c^2)
(a + bc)y/(1 - b^2) = z
multiply left equation to left.. and right equation to right equation also .
y^2/(1 - b^2) = z^2/(1 - c^2)
then you can continue with the rest of the equation ... half of the part has already been done for you .
Don't forget to SUBSCRIBE my YouTube channel (BanarasiiiINDIA) if this answer is helpful for you.This is my YouTube channel Link-https://www.youtube.com/channel/UC27NLinpXVunbzVQ0vdHabQ
Thank You!
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