If X equal to 2 minus y then show that x cube + 6 X y + y cube minus 8 equal to zero
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Explanation:
∵ x = 2 - y
∴ x³ + 6xy + y³ - 8
= (2 - y)³ +6(2 - y)y + y³ - 8
Expanding (2 - y)³ using identity (x - y)³ = x³ - y³ +3xy² - 3x²y
= 2³ - y³ + 3.2.y² - 3.2².y + 12y - 6y² + y³ - 8
= 8 - y³ + 6y² - 12y + 12y - 6y² + y³ - 8
= 0 ... Hence Proved
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