Question

if X equal to 7 + root 40 find the value of root x plus one upon root x

Answer 1

HELLO DEAR,



given that:-

x = 7 + √40

⇒ x = 7 + √(2 × 2 × 2 × 5)

⇒ x = 7 + 2(√2× √5)

⇒ x = 5 + 2 + 2(√2 × √5)

⇒ x = (√5)² + (√2)² + 2(√2 × √5)

⇒ x = (√5 + √2)²

⇒ √x = (√5 + √2)------------( 1 )


now,

1/√x = 1/(√5 + √2) * (√5 - √2)/(√5 - √2)

⇒1/√x = (√5 - √2)/(5 - 2)

⇒1/√x = (√5 - √2)/3-----------( 2 )


adding --- ( 1 ) & ----( 2 )

(√x + 1/√x) = (√5 + √2) + (√5 - √2)/3

⇒(√x + 1/√x) = [ 3√5 + 3√2 + √5 - √2 ] /3

⇒(√x + 1/√x) = (4√5 + 2√2)/3

⇒(√x + 1/√x) = 2(2√5 + √2)/3



I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

Answer:

x= 7+√40,then find value of √x +1/√x

Step-by-step explanation: