if x >0 and y>0 and z>0 then xyz <( x³ + y³ + z³ )\3
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Let x=1,y=2,z=3
therefore,1*2*3<(1+8+27)/3
6<36/3
6<12
hope it helps!!
therefore,1*2*3<(1+8+27)/3
6<36/3
6<12
hope it helps!!
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