if x is 1000 digit number,y is a sum of its digits,z is sum of the digits of yand w,then the maximum possible value of w is??
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Answer:
w can be 11, and not higher
Step-by-step explanation:
To show w can be 11
x = 999....92
y = 8993
z = 29
w = 11
To show w cannot be higher than 11:
The highest possible value of y is 9000 ( = 1000 * 9) and y can be any lower value down to 1.
The highest possible value of z is therefore 35 (from a y of 8999) and z can be any lower value down to 1.
By inspection, the highest w is achieved when z = 29 and then w = 11.
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