Question

if x is a positive integer such that the distance between points p(x 2) and q(3 -6) is 10 units, then x =

i) 3
ii) -3
iii) 9
iv) -9

Answer 1

Answer:

Distance between two points

(x2−x1)

2

+(y2−y1)

2

(x−3)

2

+(2−(−6))

2

=10

(x−3)

2

+64

=10

Squaring both sides

(x−3)

2

+64=100

x

2

−6x−27=0

x

2

−9x+3x−27=0

x(x−9)+3(x−9)=0

x=−3,9

Taking positive value, x=9units