If x is a positive integer such that the distance between points p (x,2) and Q (3,-6) is 1o units , then x =______
(a) 3
(b)(-3)
(c)9
(d)(-9)
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Answer:
9 units
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(x-3)²+(2+6)²=10²
x²-6x+9+64=100
x²-6x+73=100
x²-6x-27=0
(x-9)(x+3)=0
x= 9 or -3
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