Math, asked by yashrajgaming2908, 8 days ago

If x is a positive real number and x2 = 5, then x3 + 2 =​

Answers

Answered by chinchpur152
0

Answer:

dupdoydupdupdupduldhldlusylz

Answered by pulakmath007
1

SOLUTION

GIVEN

x is a positive real number and x² = 5

TO DETERMINE

The value of x³ + 2

EVALUATION

Here the given equation is

 \sf{ {x}^{2} = 5 }

First we find the value of x as below

 \sf{ {x}^{2} = 5 }

 \sf{ \implies {x}^{2} =  {( \sqrt{5} )}^{2}  }

Since x is a positive real number

 \sf{ \therefore \:  \: x =  \sqrt{5}  }

Now

 \sf{  {x}^{3}  + 2}

 \sf{  =  {( \sqrt{5} )}^{3}  + 2}

 \sf{  =  {( \sqrt{5}  \times  \sqrt{5} \times  \sqrt{5}  )}^{}  + 2}

 \sf{  =  {( 5 \times  \sqrt{5}  )}^{}  + 2}

 \sf{  =  5 \sqrt{5}  + 2}

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. If x=√3a+2b + √3a-2b / √3a+2b - √3a-2b

prove that bx²-3ax+b=0

https://brainly.in/question/19664646

2. the order of the surd 7√8

https://brainly.in/question/31962770

Similar questions