Question

if x is a rational number and a,b,c are all different integers then prove that
${x}^{a - b} \times {x}^{b - a} = 1$
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Answer 1

Answer:

It is given that x is a rational number .

so, the question is

${x}^{a - b} \times {x}^{b - a}$

When base are common and power are unequal , then base is taken as common and power is added.

So,

${x}^{a - b + b - a} = {x}^{0 } = 1$

so. answer is 1

Answer 2

Answer:

See this Attachment.

Step-by-step explanation:

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