Question

if x is equal to -1.2 is a solution of the quadratic equation then 3 X square + 2 x minus 3 is equal to zero find the value of k

Answer 1

Solution:

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Given:

$x = - \frac{1}{2}$

&

3x² + 2kx - 3 = 0,

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To find:

value of k
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we know that,

3x² + 2kx -3 =0 & x = $- \frac{1}{2}$

so,

=> 3($- \frac{1}{2}$)² + 2k($- \frac{1}{2}$) - 3 = 0

=> 3($\frac{1}{4}$) -k -3 = 0

=> $\frac{3}{4} -k - 3 = 0$

=> $-k = 3-\frac{3}{4}$

=>∴ $k = -2 \frac{1}{4}$

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Answer 2

Answer:

Step-by-step explanation:

X=-1/2

3(-1/2)^2+2k(-1/2)-3=0

3/4-2k/2-3=0

3/4-k=3

-k=3-3/4

-k=3*4/4-3/4

-k=12-3/4

-k=9/4

K=-9/4

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