if x is equal to 1 is a zero of the polynomial f bracket X is equals to x square - 5 x + 3 then the value of a case
ksingla:
-1
1^2-5*1+3=0
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the value is -1 of the case
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Heya!!! HERE IS YOUR ANSWER :----
which value should we find here
x=1
=1 sq -5×1+3
=1-5+3
=-4 +3
=-1
hence 1 is not a zero of the polynomial f (x)
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which value should we find here
x=1
=1 sq -5×1+3
=1-5+3
=-4 +3
=-1
hence 1 is not a zero of the polynomial f (x)
@@@@@@HOPE IT HELPS U N PLZ MARK ME AS BRAINLIEST ☆☆☆☆☆☆
happ
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