if x is equal to 1 upon 3 root minus minus root 2 then find the value of x square + 1 upon x square
Answers
Answered by
1
Step-by-step explanation:
x=3+2
2
x
1
=
3+2
2
1
×
3−2
2
3−2
2
=3−2
2
(
x
−
2
1
)
2
=x+
x
1
−2
=3+2
2
+3−2
2
−2=4
So,
x
−
x
1
=
4
=±12 Ans
Answered by
0
Answer:
433/19+6√2
Step-by-step explanation:
x=1/3-(-√2) (Given)
Solution:
x^2= 19+6√2(by solving)
To find:x^2+1/x^2
=x^4+1/x^2
={1/3-(-√2)}^4/x^2
={{1/3-(-√2)}^2}^2/x^2
={{1+3√2/3}^2}^2/x^2
={1+18+6√2}^2/x^2
={19+6√2}^2/x^2
={361+72}/x^2
=433/19+6√2
Similar questions