Math, asked by vivek688227, 6 months ago

if x is equal to 1 upon 3 root minus minus root 2 then find the value of x square + 1 upon x square​

Answers

Answered by prathamjadon22
1

Step-by-step explanation:

x=3+2

2

x

1

=

3+2

2

1

×

3−2

2

3−2

2

=3−2

2

(

x

2

1

)

2

=x+

x

1

−2

=3+2

2

+3−2

2

−2=4

So,

x

x

1

=

4

=±12 Ans

Answered by pradyumnchaudhary6
0

Answer:

433/19+6√2

Step-by-step explanation:

x=1/3-(-√2) (Given)

Solution:

x^2= 19+6√2(by solving)

To find:x^2+1/x^2

=x^4+1/x^2

={1/3-(-√2)}^4/x^2

={{1/3-(-√2)}^2}^2/x^2

={{1+3√2/3}^2}^2/x^2

={1+18+6√2}^2/x^2

={19+6√2}^2/x^2

={361+72}/x^2

=433/19+6√2

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