Question

if x is equal to √2 + 1 find the value of x cube + 1 / x cube​

Answer 1

I think this is the answer

Answer 2

so

X=

$\sqrt{2 } + 1$

then 1/x=

$1 \div \sqrt{2} + 1$

then rationalizing the denominator

we get

$\sqrt{2} - 1$

then

X cube + 1/X cube=

$( \sqrt{2} + 1) ^{3} + ( \sqrt{2} - 1) {}^{3}$

$\sqrt{2} ^{3} + 1 ^{3} + \sqrt{2} {}^{3} - 1 ^{3}$

positive 1 and negetive 1 gets cancelled

then left is

$\sqrt{2} ^{3} + \sqrt{2} {}^{3}$

$(2 \sqrt{2}) {}^{3}$

hope it helps

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