If x is equal to 3 is one of the root of the equation x^2-2kx-6is equal to 0 then find the value of k.
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1
Hey mate...
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@Rêyaañ11
Here's your answer...
===========================
Refer to the attachment...✌
HOPE IT HELPS
@Rêyaañ11
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Ishikachauhan83:
Thnku
Answered by
4
p(x)=x²-2kx-6
g(x)=x-3
=>x=3
Put in p(x)
(3)²-2k(3)-6=0
9-6k-6=0
3-6k=0
-6k=-3
k=-3/-6
k=1/2
g(x)=x-3
=>x=3
Put in p(x)
(3)²-2k(3)-6=0
9-6k-6=0
3-6k=0
-6k=-3
k=-3/-6
k=1/2
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