if x is equal to 4 minus root 15 find the value of root x + 1 upon root x
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root 6
Step-by-step explanation:
If x=4-root15
Therefore, 1/x=1/4-root15
=1/(4-root15)×(4+root15)/(4+root15)
=1×(4+root)/(4)^2-(root15)^2 {As (a+b)(a-b)=a^2-b^2}
=4+root15/16-15
=4+root15
1/x=4+root15
Now (x+1/x)=(root x+1/root x)^2-2×root x×1/root x
(x+1/x)=(root x+1/root x)^2-2 { root x and 1/root x deducted}
Putting value of x and 1/x in LHS
(4-root 15+4+root 15)=(root x+1/root x)^2-2
4=(root x +1/root x)^2-2 {-root 15+root 15 =0}
4+2=(root x +1/ root x)^2
6=(root x+1/root x)^2
Square rooting both sides
root 6=root(root x+1/root x)^2
Therefore, rootx+1/root x=root6
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