If x is equal to a sec theta + b tan theta and y is equal to a tan theta + b sec theta prove that x square minus y square is equal to a square minus b square
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x² - y² = a² - b² if x = asecθ + btanθ & y = atanθ + bsecθ
Step-by-step explanation:
x = asecθ + btanθ
y = atanθ + bsecθ
to be proved
x² - y² = a² - b²
LHS
= x² - y²
= (x + y)(x - y)
= (asecθ + btanθ + atanθ + bsecθ)(asecθ + btanθ - atanθ - bsecθ)
= (a(secθ + tanθ) + b(secθ + tanθ))(a(secθ - tanθ) - b(secθ - tanθ))
= (a + b)(secθ + tanθ)(a - b)(secθ - tanθ)
= (a + b)(a - b)(secθ + tanθ)(secθ - tanθ)
= (a² - b²)(sec²θ - tan²θ)
= (a² - b²)1
= a² - b²
= RHS
QED
Learn more:
x= Acos +Bsin , y= Asin- Bcos prove that x²+y²=a²+b²
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