If x is equal under root 5 plus 2 under root 6 / 5- 2 under root 6 evaluate x² ( x -10)²
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Step-by-step explanation:
(2x+3y)2=(2x)2+2(2x)(3y)+(3y)2
=4x2+12xy+9y2
Aliter: (2x+3y)2=(2x+3y)(2x+3y)
=2x(2x+3y)+3y(2x+3y)
=(2x)(2x)+(2x)(3y)+(3y)(2x)+(3y)(3y)
=4x2+6xy+6yx+9y2[∵xy=yx]
(2x+3y)2=4x2+12xy+9y2
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