if x is equals to 3 is one root of quadratic equation X square - 2k x minus 6 is equals to zero then find the value of k
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3
x = 3
x2 - 2kx -6 = 0
3^2 - 2(3)k - 6 = 0
9 - 6k - 6 = 0
3 - 6k = 0
3 = 6k
k = 3/6
= 1/2
= 0.5
Hpe the answer is correct........
x2 - 2kx -6 = 0
3^2 - 2(3)k - 6 = 0
9 - 6k - 6 = 0
3 - 6k = 0
3 = 6k
k = 3/6
= 1/2
= 0.5
Hpe the answer is correct........
nikitadas2801:
Yess the answer is correct
Answered by
2
x^2 - 2kx - 6 = 0
3^2 - 2k×3 - 6 = 0
9 - 6k -6 = 0
3 - 6k = 0
-6k = -3
k = -3/-6
Hence, k = 1/2
3^2 - 2k×3 - 6 = 0
9 - 6k -6 = 0
3 - 6k = 0
-6k = -3
k = -3/-6
Hence, k = 1/2
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