Question

if x is equals to 3 power 1 by 3 + 3 power minus 1 by 3 then 3 x cube minus 10 is​

Answer 1

$x=3^{\frac{1}{3} } +3^{\frac{-1}{3} }\\\\3x^{3} -10=3(3^{\frac{1}{3} } +3^{\frac{-1}{3} })^{3} -10\\3x^{3}-10 =3[3+3^{-1} +3*3^{\frac{1}{3} } *3^{\frac{-1}{3} }(3^{\frac{1}{3} } +3^{\frac{-1}{3} })]\\3x^{3} -10=3[3+\frac{1}{3} +3(3^{\frac{1}{3} }+ \frac{1}{3^{\frac{1}{3} }} )]\\\3x^{3}-10=3[\frac{9+1}{3} +3(\frac{3^{\frac{2}{3} }+1 }{3^{\frac{1}{3} } } )] \\3x^{3} -10=3[\frac{10}{3}+\frac{3*3^{\frac{2}{3} }+3*1 }{3^{\frac{1}{3} } } ]$$3x^{3} -10=10+\frac{3*3*3^{\frac{2}{3} }+3*3*1 }{3^{\frac{1}{3} } } \\3x^{3} -10=10+\frac{3^{\frac{2}{3}+2 }+9 }{3^{\frac{1}{3} } } \\3x^{3} -10=10+\frac{3^{\frac{8}{3} }+9 }{3^{\frac{1}{3} } } \\3x^{3} -10=10+\frac{3^{\frac{8}{3} }}{3^{\frac{1}{3} }} +\frac{9}{3^{\frac{1}{3} }} \\3x^{3} -10=10+3^{\frac{8}{3} -\frac{1}{3} } +3^{2-\frac{1}{3} }\\3x^{3} -10=10+3^{\frac{7}{3} }+3^{\frac{5}{3} }$

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