if x is equals to under root 5 + under root 2 upon under root 5 minus under root 2 and Y is equals to under root 5 minus under root 2 upon under root 5 + under root 2 show that 3 a square + 4 AV minus 3 b square equal to 4 + 56 upon 3 under root 10
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X = √(3+1)/√(3-1)
=√4/√2
=√2
Y = √(3-1)/√(3+1)
=√2/√4
=1/√2
X^2 + XY - Y^2 =
(√2)^2 + (√2)(1/√2) -(1/√2)^2
=2+1 -1/2
= 3 + 1/2
= 7/2
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