Question

If x is midway between 10 and 16 and y is half of 78 what is y/x

Answer 1

The value of $\frac{y}{x}$.

Step-by-step explanation:

Given:

$x$ is midway between 10 and 16.

$y$ is half of 78.

To Find:

The value of $\frac{y}{x}$.

Solution:

As given,  $x$ is midway between 10 and 16.

   $x=13$

As given,$y$ is half of 78.

$y=\frac{78}{2} =39$

The value of $\frac{y}{x} =\frac{39}{13} =3$

Thus,the value of $\frac{y}{x}$ is 3.

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Answer 2

Answer:

3 is the required value of $\frac{y}{x}$.

Explanation:

Given that, x is midway between 10 and 16.

This means x is the mid point of 10 and  16

⇒ x = $\frac{10 + 16}{2}$ = $\frac{26}{2}$ = 13

Now, from the question y is the half of 78.

⇒ y = $\frac{78}{2}$ = 39

According to the question we need to find out the value of $\frac{y}{x}$.

So, we have, x = 13 and y = 39.

Now, we put the value of x = 13 and y  = 39 in $\frac{y}{x}$.

⇒ $\frac{y}{x}$ = $\frac{39}{13}$ = 3

Final answer:

Hence, 3 is the required value of $\frac{y}{x}$.

#SPJ2