Question

if x is real Find the least value of x square - 6 X + 10

Answer 1

x^2-6x+10

x=-b +-√b^2+4ac÷2a

here b=-6
a=1
c=10
applying in the equation
x=-(-6)+-√(-6)^2+4.1.10÷2.1
.=6+√36+40÷2
=6+√76÷2
=6+√4.36÷2
= 6+2√36÷2
taking 2 common and cancelling
=3+-√36


x=3+√36
or
x=3-√36