Question

If x' is real
Рrove that x/x^2-5x+9 lies between-1/11 and 1​

Answer 1

Answer:

Hence, proved that  x/x^2-5x+9 lies between-1/11 and 1​

Step-by-step explanation:

Take x/x^2-5x+9 = y

then by cross multiplying,

x = y(x^2-5x+9)

x = x^2y - 5xy + 9y  ⇒   x^2 - x( 5y + 1) + 9y = 0

Find discriminant, as d ≥ 0

Then by solving the equation by sign scheme method, answer comes out to be true.

hence, proved

Answer 2

Step-by-step explanation:

The solution is in this photo check your answer