Question

If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18, what is the average of x, y, and z in terms of m?

A) m+6
B) m+7
C) 2m+14
D) 3m+21

Answer 1

Answer:

this is your answer.......,..m+7

Answer 2

x = (m+9)/2

y = (2m+15)/2

z = (3m+18)/2

.•. Average of x,y,z

= (x + y +z)/3

= (((m+9)/2)+((2m+15)/2)+((3m+18)/2)))/3

= ((m+9+2m+15+3m+18)/2)/3

= (6m + 42)/(2*3)

= 6(m + 7)/6

= m + 7

So, option B is right ...

Hope it helps you...

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