Chemistry, asked by rathoresingh7229, 7 months ago

If x is the radius of first
Bohr's orbit of H-atom, the de-
Broglie's wavelength of an
electron revolving in the 2nd
Bohr's orbit will be​

Answers

Answered by cosmiccreed
0

Answer:

rn =radius of n th orbit

And

r2=n^2r

=4r

=4x

MV4x=2h/2π

MV4X=h/π

h/mv=4πx

Explanation:

Answered by venkatakshayg
0

FORMULA FOR RADIUS OF ORBIT=0.529×n²/z² Armstrong's

GIVEN THAT,

X=0.529×1²/1²

IT IS WRITTEN LIKE THAT AS IT IS FIRST ORBIT AND FIRST ELEMENT

n IS ORBIT NO.

z IS ATOMIC NO.

FOR SECOND ORBIT

R[RADIUS] OF SECOND ORBIT=0.529×2²/1²=0.529×4

X=0.529

RADIUS OF SECOND ORBIT=0.529×4=4X

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