If x is the radius of first
Bohr's orbit of H-atom, the de-
Broglie's wavelength of an
electron revolving in the 2nd
Bohr's orbit will be
Answers
Answered by
0
Answer:
rn =radius of n th orbit
And
r2=n^2r
=4r
=4x
MV4x=2h/2π
MV4X=h/π
h/mv=4πx
Explanation:
Answered by
0
FORMULA FOR RADIUS OF ORBIT=0.529×n²/z² Armstrong's
GIVEN THAT,
X=0.529×1²/1²
IT IS WRITTEN LIKE THAT AS IT IS FIRST ORBIT AND FIRST ELEMENT
n IS ORBIT NO.
z IS ATOMIC NO.
FOR SECOND ORBIT
R[RADIUS] OF SECOND ORBIT=0.529×2²/1²=0.529×4
X=0.529
RADIUS OF SECOND ORBIT=0.529×4=4X
Similar questions