Math, asked by 1239098, 10 months ago

If x=k √2 be a solution of the quadratic x + √2x-4=0, then k = (c) 2 (b) - 2 (a) - 1 (d) 4

Answers

Answered by pulakmath007
0

Answer:

The answer is (b) - 2

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Answered by notryanjacob
0

Answer:

(b) -2

Step-by-step explanation:

Solve given quadratic :

x = \frac{-\sqrt{2} +- \sqrt{18}  }{2} \\

you get

x = \frac{-\sqrt{2}+3\sqrt{2}  }{2}  OR x = \frac{-\sqrt{2}-3\sqrt{2}  }{2}

simplifying

x=\frac{2\sqrt{2} }{2} = 1\sqrt{2}  OR x = \frac{-4\sqrt{2} }{2} = -2\sqrt{2}

By comparing,

k = 1  OR k = -2.

Hence option (b) is correct

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