Question

If x+ky-4=0 and 2x+4y-12=0 are parallel then find the value of k

Answer 1

Solution :

Compare x + ky - 4 = 0

and

2x + 4y - 12 = 0 with

a1x + b1y + c1 = 0

and

a2x + b2y + c2 = 0 , we get

a1 = 1 , b1 = k , c1 = -4 ,

a2 = 2 , b2 = 4 , c2 = -12,

a1/a2 = b1/b2 [ parallel lines ]

=> 1/2 = k/4

=> 4/2 = k

=> 2 = k

Therefore ,

k = 2

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