Question

if x=log 2 to the base 15, y=log 3 to the base 10, z=log 5 to the base 6, then show that xy+yz+zx+2xyz=1​​

Answer 1

Answer:

15^x=2

10^y=3

6^z=5

ylog10=log3

y=log3/log10

y=.4771

..

zlog6=log5

z=log5/log6

z=.8982

..

xy+yz+zx+2xyz

=.2560*.4771+.4771*.8982+.8982*2360+2*.2560*.4771*.8982

=.1221+.4285+.2120+.2194

=.9820

Explanation:

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