Question

The value of 6a²b² - 4ab, where a = 2& b = 1 is ______________​

Answer 1

Answer:

hope it's helpful

Step-by-step explanation:

6a^2 b^2 -4ab

a=2 and b=-1

6(2)^2 (-1)^2- 4-(2) (-1)

6(4) (1) - 4(2) (-1)

24+8 = 32

Answer 2

Answer:

The value of $6a^{2} b^{2} - 4ab$ is 6 .

Step-by-step explanation:

Given -

a = 2

b = 1

To find -

The value of $6a^{2} b^{2} - 4ab$

Solution -

Given equation ,

$6a^{2} b^{2} - 4ab$

Put the value of a = 2 And b = 1 we get

= $6\times2^{2} \times1^{2} - 4\times2\times1$

The square means the multiply the number with itself .

∴ $2^{2} = 4$

$1^{2} = 1$

Put these value in the equation

= $6\times4 \times1 - 4\times2\times1$

= $24-8$

= $16$

∴ The value of $6a^{2} b^{2} - 4ab$ is 6 .