If x=log2/3 y=3/5 and z=2 log (5/2)^1/2 find values of x+y+z and 5^x+y+z
Answers
Answered by
2
x=log2/3 =log2-log3
y=3/5
z=2 log (5/2)^1/2=log(5/2)
=log5-log2
x+y+z=(log2-log3)+(3/5)+(log5-log2)
=log5-log3+3/5
=log(5/3)+3/5
Similar questions