Math, asked by mrigankjaigmailcom, 9 months ago

If x logy +ylog x = 1, then the
:value of y^x ×. x^y is

Answers

Answered by 217him217
2

Answer:

xlogy + ylogx=1

=> logy^x + logx^y = log10

=> log( y^x * x^y) = log10

=> y^x*x^y = 10

Similar questions