Question

The present age of a man is twice than of his son. Eight years after, there age will be in the ratio 7:4. Find there present age​

Answer 1

Answer:

Present age X=1:2

X+8 years=7:4

2x+8/x+8=7/4

8x+32=7x+56

x=24

father's age is 48 and son's age is 24

Step-by-step explanation:

Answer 2

Solution:

Let:

The present age of man=2x

The present age of his son=x

8 year's later ,

The age of man=2x+8

The age of his son=X+8

A.T.Q

After 8 year's their age will be in the ratio 7:4

$\sf{\dashrightarrow \dfrac{2x+8}{x+8}=\frac{7}{4}}$

$\sf{\dashrightarrow 4(2x+8)=7(X+8)}$

$\sf{\dashrightarrow 8x+32=7X+56}$

$\sf{\dashrightarrow 8x-7x=56-32}$

$\sf{\dashrightarrow x=24}$

Hence,

The present age of son=24 year's

The present age of man=2×24=48 year,s