if x minus 1 by x = 3 . find x cube minus 1 by x cube
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x - (1/x) = 3
We are aware of the identity
a³ - b³ = (a - b)³ + 3ab(a - b)
So
x³ - (1/x)³
= (x - 1/x)³ + 3*x*(1/x)*(x - 1/x)
= 3³ + 3×1×3
= 27 + 9
= 36
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Answered by
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Answer:
x-1 = 3x
-1 = 3x - x
-1= 2x
x = -1/2
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