Question

if x minus 3 and x minus 1 over 3 are factors of P X square + 5 x + r then prove that p= r
plz answer it. its urgent!!!!!!!

Answer 1

Given f(x) = px^2 + 5x + r.

(x-3) is a factor of f(x), so f(3) = 0

               = p(3)^2 + 5(3) + r

               = 9p + 15 + r = 0  --- (1)


Given (x-1/3) is a factor of f(x), so f(1/3) = 0

              = p(1/3)^2 + 5(1/3) + r = 0

             = p/9 + 5/3 + r = 0

             = p + 15 + 9r = 0   --- (2)


On solving (1) and (2), we get

9p + 15 + r = 0

p + 15 + 9r = 0

-------------------------

8p - 8r = 0

p = r.


Hope this helps!

Answer 2

Answer:

I HOPE THIS MAY HELP YOU !!!!!!!!!!!!!!