if x minus 3 is a factor of x square + kx + 9 then find the value of k
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given x-3
suppose x=3
put the value of x in equation
x^2+kx+9=0
(3)^2+3k+9=0
9+3k+9=0
3k=-9-9
3k=-18
k=-18/3
k=-6
suppose x=3
put the value of x in equation
x^2+kx+9=0
(3)^2+3k+9=0
9+3k+9=0
3k=-9-9
3k=-18
k=-18/3
k=-6
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SakshamMahajan007:
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