Math, asked by tesvinny2114, 1 year ago

if x minus one upon X equal to 3 + 2 root 2 find the value of x cube minus one up on x cube

Answers

Answered by ishwarsinghdhaliwal
207

x -  \frac{1}{x}  = 3 + 2 \sqrt{2}  \\ on \: cubing \: \: we \: get \\ (x -  \frac{1}{x} ) ^{3}  = (3 + 2 \sqrt{2} )^{3}  \\  {x}^{3}  -  \frac{1}{x ^{3} }  + 3( {x})^{2} ( \frac{ - 1}{x} ) + 3(x)( \frac{ - 1}{x} ) ^{2}  =  ({3})^{3}  + (2 \sqrt{2} )^{3}  + 3( {3})^{2} (2 \sqrt{2} ) + 3(3)(2 \sqrt{2} ) ^{2}  \\  {x}^{3}  -  \frac{1}{x ^{3} }  - 3x +  \frac{3}{x}  = 27 + 16 \sqrt{2}  + 54 \sqrt{2}  + 48 \\  {x}^{3}  -  \frac{  1}{x^{3} }  - 3(x -  \frac{1}{x} ) = 75 + 70 \sqrt{2}  \\ {x}^{3}  -  \frac{  1}{x^{3} }  - 3(3 + 2 \sqrt{2} ) = 75 + 70 \sqrt{2}  \\ {x}^{3}  -  \frac{  1}{x^{3} }  - 9 - 6 \sqrt{2}  = 75 + 70 \sqrt{2} \\ {x}^{3}  -  \frac{  1}{x^{3} }  = 75 + 70 \sqrt{2} +  9  + 6 \sqrt{2} \\ {x}^{3}  -  \frac{  1}{x^{3} } = 84 + 76 \sqrt{2}

Sandeepdas03: Wrong answer
Answered by uuhgy
153
HELLO ,
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