Question

If x = p sec θ and y = q tan θ , then [1] (a) x2− y2 = p2q2 (b) x2q2− y2p2 = pq (c) x q y p p q 2 2 2 2 1 2 2 − = (d) x2q2− y2p2 = p2q2

Answer 1

Step-by-step explanation:

Statement => x^2/ p^2 - y^2/q^2 = 1

=> x^2 q^2 - y^2 p^2 = p^2 q^2