If x = p seco+ p tano and y =p tano + p seco then prove that
x2-y2=p2-q2 answer plz
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Answered by
5
Answer:
Step-by-step explanation:
x = p secФ+ q tanФ
y =p tanФ + q secФ
x²-y² =(p secФ+ q tanФ)²-(p tanФ + q secФ)²
=(p² sec²Ф+ q² tan²Ф+2pq secФtanФ) - ( p² tan²Ф+ q² sec²Ф+2pq secФtanФ)
=p² (sec²Ф- tan²Ф) +q²( tan²Ф- sec²Ф)
=p²*1+q²(-1)
=p²-q² =RHS
Answered by
3
☺answer:
upper answer is right...
sorry
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