if x plus one upon X equals to 4 find the value of x cube plus one upon x cube
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Answered by
32
(x+1/x)^3=x^3+1/x^3+3(x+1/x)
(x+1/x)^3-3(x+1/x)=x^3+1/x^3
4^3-3(4)= x^3+1/x^3
64-12=52
(x+1/x)^3-3(x+1/x)=x^3+1/x^3
4^3-3(4)= x^3+1/x^3
64-12=52
Answered by
26
x+1/x=4
cubing both sides
x^3+1/x^3+3x^2*1/x+3x*1/x^2=64
x^3+1/x^3+3x+3/x=64
x^3+1/x^3+3(x+1/x)=64
x^3+1/x^3+3*4=64
x^3+1/x^3=64-12
x^3+1/x^3=52
hope this helps:p
cubing both sides
x^3+1/x^3+3x^2*1/x+3x*1/x^2=64
x^3+1/x^3+3x+3/x=64
x^3+1/x^3+3(x+1/x)=64
x^3+1/x^3+3*4=64
x^3+1/x^3=64-12
x^3+1/x^3=52
hope this helps:p
Anonymous:
do mark as brainliest:p
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