Question

if x plus one upon x is equal to 12 then the value of x minus one upon X is​

Answer 1

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$x - \frac{1}{x} = \frac{ + }{} \sqrt{140}$

Answer:

$x + \frac{1}{x} = 12 \\ \\ {(x + \frac{1}{x} )}^{2} - {(x - \frac{1}{x} )}^{2} = 4 \\ \\ {(x - \frac{1}{x} )}^{2} = ({12})^{2} - 4 \\ \\ {(x - \frac{1}{x} )}^{2} = 140 \\ \\ x - \frac{1}{x} = \frac{ + }{} \sqrt{140}$