Question

If x plus one upon x is equal to 2 find the value of x cube + 1 upon x cube

Answer 1

Answer:

$\frac{ {x}^{3} + 1}{ {x}^{3} } = 2$

Step-by-step explanation:

$\frac{x + 1}{x} = 2$

$x + 1 = 2x \\ \implies \: x = 1$

$\frac{ {x}^{3} + 1}{ {x}^{3} } = \frac{ {1}^{3} + 1}{ {1}^{3} } = 2$

Answer 2

Step-by-step explanation:

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