Question

if x plus one upon X is equals to 5 then find x cube + 1 upon x cube​

Answer 1

Answer:

$x + \frac{1}{x} = 5 \\ \\ qube \: \: both \: \: side \\ \\ {x}^{3} + \frac{1}{ {x}^{3} } + 3(x + \frac{1}{x} ) = 125 \\ \\ {x}^{3} + \frac{1}{ {x}^{3 } } + 3(5) = 125 \\ \\ {x}^{3} + \frac{1}{ {x}^{3} } = 125 - 15 = 110$