If x power 2 = y power 2 then
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Answer:
We have,
x
2
+y
2
=t−
t
1
and x
4
+y
4
=t
2
+
t
2
1
⇒(x
2
+y
2
)
2
=(t−
t
1
)
2
⇒x
4
+y
4
+2x
2
y
2
=t
2
+
t
2
1
−2
⇒x
4
+y
4
+2x
2
y
2
=x
4
+y
4
−2 [given]
⇒2x
2
y
2
=−2
⇒x
2
y
2
=−1
⇒y
2
=−
x
2
1
⇒y
2
=−x
−2
Differentiating w.r.t. x, we get,
⇒2y
dx
dy
=−(−2)x
−3
⇒y
dx
dy
=
x
3
1
∴
dx
dy
=
x
3
y
1
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