If x = r sin a×cosß, y = r sin a ×cosB and z = r cos a, then x + y
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2r sina cosβ
Step-by-step explanation:
given the value of x, y, z
so we find the x+y
putting x and y value on it
x+y = (r sina cosβ) + (r sina cosβ)
= 2r sina cosβ
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