Question

if x€R then find minimum value of |x-1|2x-1|.... |119x-1|​

Answer 1

Answer:

x−1∣+∣2x−1∣+∣3x−1∣+......+∣119x−1∣

=x−1+2x−1+3x−1+....+119x−1

=x(1+2+3....+119)−119

=x(

2

119×120

)−119

=119(60x−1) .

Minimum value= 0 occurs when 60x−1=0

⇒60x=1

⇒x=1/60 .

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